davidbrown3 : Rotating Frames of Reference

Consider two frames of reference, AA and BB. Frame AA is stationary and can be said to be inertial. Frame BB is rotating relative to frame AA.

A point in space, PP can be located using a vector observed in either frame of reference and expressed using a combination of their respective ii, jj and kk components;

vA=[xiA;xjA;xkA] v^A = [x_{i}^A;x_{j}^A;x_{k}^A]

vB=[xiB;xjB;xkB] v^B = [x_{i}^B;x_{j}^B;x_{k}^B]

The velocity of point PP as observed from either frame of reference can also be expressed using the derivative of the same components;

vA˙=[xiA˙;xjA˙;xkA˙] \dot{v^A} = [\dot{x_{i}^A};\dot{x_{j}^A};\dot{x_{k}^A}]

vB˙=[xiB˙;xjB˙;xkB˙] \dot{v^B} = [\dot{x_{i}^B};\dot{x_{j}^B};\dot{x_{k}^B}]

If the rotation matrix that transforms reference frame AA to BB is known and expressed as RABR_{A}^{B} then an additional expression can be written that expresses the position vector expressed in reference AA to the same vector expressed in reference BB;

vB=RABvA v^B =R_{A}^{B}\cdot{v}^A

By chain-rule differentiation it is also possible to write an expression relating the velocity of point PP expressed in reference AA to the same velocity expressed in reference BB;

vB˙=RAB˙vA+RABvA˙ \dot{v^B} = \dot{R_{A}^{B}}\cdot{v}^A+R_{A}^{B} \cdot\dot{v^A}

Using the same method again, an expression relating the acceleration of point PP​ expressed in reference AA​ to the same acceleration expressed in reference BB​ can be written;

vB¨=(RAB¨vA+RAB˙v˙A)+(RABvA¨+RAB˙vA˙) \ddot{v^B} = (\ddot{R_{A}^{B}}\cdot{v}^A+\dot{R_{A}^{B}}\cdot{\dot{v}^A})+(R_{A}^{B} \cdot\ddot{v^A}+\dot{R_{A}^{B}} \cdot\dot{v^A})

The expressions of this can be grouped to form the equation;

vB¨=2RAB˙vA˙+RAB¨vA+RABvA¨ \ddot{v^B} = 2\cdot\dot{R_{A}^{B}} \cdot\dot{v^A}+\ddot{R_{A}^{B}}\cdot{v}^A+R_{A}^{B} \cdot\ddot{v^A}

Expression Description
2RAB˙vA˙2\cdot\dot{R_{A}^{B}}\cdot\dot{v^A} Coriolis Term
RAB¨vA\ddot{R_{A}^{B}}\cdot{v}^A Centripetal Term
RABvA¨R_{A}^{B} \cdot\ddot{v^A} Rotated Acceleration

From Netwons first law we can relate acceleration in an inertial frame to the force applied;

FA=MvA¨ F^A= M\cdot\ddot{v^A}

Inserting this into the previous equation;

vB¨=2RAB˙vA˙+RAB¨vA+RABFAM \ddot{v^B} = 2\cdot\dot{R_{A}^{B}} \cdot\dot{v^A}+\ddot{R_{A}^{B}}\cdot{v}^A+R_{A}^{B} \frac{F^A}{M}

It is seen that the Coriolis and Centripetal terms are interpreted as if they themselves were forces, which is why they are often called 'Apparent Forces'. However, there is no physical origin behind them nor do they create any reaction force. Their existence is purely a result of matrix transformations.